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6 m 2 Y usando el método de componentes. B ∙ C= B x C x + B y C y = (11. 49m)( -3m) + (-9. 64m)(-5. 2m)= 15. 6 m 2 Respuesta: B ∙ C= 15. 6m 2 c) A= 12m y C = 6m el ángulo entre ellos es (90-60) + (90) + (90-37) = 173° A ∙ C= (12m)(6m)cos173°= -71. 5 m 2 Con el segundo método: A ∙ C= A x C x + A y C y = (7. 22m)(-3m) + (9. 58m)(-5. 2m)= -71. 5 m 2 Respuesta= A ∙ C= -71. 5 m 2
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